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Question

Find the value of sinn1890+cosecn1890. Where nN


A

n

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B

2n

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C

1

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D

2

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Solution

The correct option is D

2


When we see the angle more then 360. We will write those angles as (n×360+θ) where nN

1890 = 360×5+90

sin(360×5+90)=sin90=1

and cosec (360×5+90)=cosec 90=1

So, sinn (360×5+90)=1
cosec n (360× 5 + 90)=1

=sinn 90+cosecn 90

=1+1

=2


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