Question

Find the value of $\sqrt[3]{3288}\times \sqrt[3]{3432}\times \sqrt[3]{3648}$.

• A. 432
• B. 565
• C. 469
• D. 328

Answer 1

The correct option is A 432

$\sqrt[3]{3288}\times \sqrt[3]{3432}\times \sqrt[3]{3648}=\sqrt[3]{3288\times 432\times 648}=\sqrt[3]{32^5\times 3^2\times 2^4\times 3^3\times 2^3\times 3^4}=\sqrt[3]{32^{12}\times 3^9}=2^4\times 3^3=432$