Question

Find the value of ${\tan }^2{60}^{\circ }+2{\tan }^2{45}^{\circ }$.

Answer 1

As

$\tan {60}^{\circ }=\sqrt{3}$

$\tan {45}^{\circ }=1$

${\tan }^2{60}^{\circ }+{\tan }^2{45}^{\circ }=(\sqrt{3}{)}^2+(1{)}^2=3+1=4$

Hence the value is 4.