Find the value of tan16°32'.
(Refer the trigonometric table for the values)

0.2986

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0.2869

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0.2968

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0.9268

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Solution

The correct option is C 0.2968
We can write,
16°32' = 16°30' + 2'
From the table we have, tan16°30' = 0.2962
Mean difference for, 2′ = 6

tan16°30' = 0.2962
+ 2′ = 6 (Mean difference to be added for tan)
____________________
tan16°32' = 0.2968

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