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Question

Find the value of the determinant ∣ ∣bccaabpqr111∣ ∣, where a, b and c are respectively the pth, qth and rth terms of a harmonic progression.

A
1
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B
pqr
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C
\N
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D
1abc
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Solution

The correct option is C \N
Since, a, b, c are pth, qth and rth terms of HP.
1a,1b,1c are in an AP.
1a=A+(p1)D1b=A+(q1)D1c=A+(r1)D⎪ ⎪ ⎪⎪ ⎪ ⎪ . . . (i)
Let Δ=∣ ∣bccaabpqr111∣ ∣=abc∣ ∣ ∣1a1b1cpqr111∣ ∣ ∣ [from Eq. (i)]
=abc∣ ∣A+(p1)DA+(q1)DA+(r1)Dpqr111∣ ∣Applying R1R1(AD)R3DR2=abc∣ ∣000pqr111∣ ∣=0∣ ∣bccaabpqr111∣ ∣=0

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