Question

Find the value of the expression $(36x^2+25y^2+60xy)$ , when $x=\frac{1}{5}$ and $y=\frac{4}{3}$

Answer 1

Consider the given expression,

$(36x^2+25y^2+60xy)$ at $x=\frac{1}{5}$and$y=\frac{4}{3}$

$\Rightarrow 36{\left(\frac{1}{5}\right)}^2+25{\left(\frac{4}{3}\right)}^2+60\times (\frac{1}{5}\times \frac{4}{3})$

$\Rightarrow 36\left(\frac{1}{25}\right)+25\left(\frac{16}{9}\right)+60\times \left(\frac{4}{15}\right)$

$\Rightarrow \frac{36}{25}+\frac{400}{9}+16$

$\Rightarrow \frac{13924}{225}$

Hence, the value of the expression is $\frac{13924}{225}$.