Find the value of the expression

$(64 x^{2} + 81 y^{2} + 144 x y)$ when $x = 11$ and $y = \frac{4}{3}$

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Solution

$64 x^{2} + 81 y^{2} + 144 x y = (8 x)^{2} + (9 y)^{2} + 2 \times 8 x \times 9 y = (8 x + 9 y)^{2} = {(8 \times 11 + 9 \times \frac{4}{3})}^{2} = (88 + 12)^{2} = (100)^{2} = 10000$

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Similar questions

Q. Find the value of the expression (64x² + 81y² + 144xy), when x = 11 and

y = \frac{4}{3} .

Find the values of the following expressions:

$(i) 16 x^{2} + 24 x + 9, w h e n x = \frac{7}{4} (i i) 64 x^{2} + 81 y^{2} + 144 x y, w h e n x = 11 a n d y = \frac{4}{3} (i i i) 81 x^{2} + 16 y^{2} - 72 x y, w h e n x = \frac{2}{3} a n d y = \frac{3}{4}$

Q. Find the values of the following expressions:
(i) 16x² + 24x + 9, when

x = \frac{7}{4}

(ii) 64x² + 81y² + 144xy, when x = 11 and

y = \frac{4}{3}

(iii) 81x² + 16y² − 72xy, when

x = \frac{2}{3}

and

y = \frac{3}{4}

Find $64 x^{2} + 81 y^{2} + \frac{144 x y}{48}$ when $x = 11$ and $y = \frac{4}{3}$

Q. Find the value of the expression

(36 x^{2} + 25 y^{2} + 60 x y)

, when

x = \frac{1}{5}

and

y = \frac{4}{3}

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Find the value of the expression (64x2+81y2+144xy) when x=11 and y=43

64x2+81y2+144xy=(8x)2+(9y)2+2×8x×9y=(8x+9y)2=(8×11+9×43)2=(88+12)2=(100)2=10000

Find the value of the expression

$(64 x^{2} + 81 y^{2} + 144 x y)$ when $x = 11$ and $y = \frac{4}{3}$

$64 x^{2} + 81 y^{2} + 144 x y = (8 x)^{2} + (9 y)^{2} + 2 \times 8 x \times 9 y = (8 x + 9 y)^{2} = {(8 \times 11 + 9 \times \frac{4}{3})}^{2} = (88 + 12)^{2} = (100)^{2} = 10000$