Find the value of the expression -1 x-1 x-1 -sin -1 x-1 x-1 -

=^ 1 ( x+1 x 1 #160; ) +sin^ 1 ( x 1 x+1 #160; ) =cos^ 1 ( x 1 x+1 #160; ) +sin^ 1 ( x 1 x+1 #160; ) =π #160; 2 #16 ...

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Basic Inverse Trigonometric Functions

Find the valu...

Question

Find the value of the expression ${sec}^{- 1} (\frac{x + 1}{x - 1}) + {sin}^{- 1} (\frac{x - 1}{x + 1})$ .

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{sec}^{- 1} (\frac{x + 1}{x - 1}) + {sin}^{- 1} (\frac{x - 2}{x + 1})

{sec}^{- 1} (\frac{x + 1}{x - 1}) + {sin}^{- 1} (\frac{x - 1}{x + 1})

y = s e c^{- 1} (\frac{x + 1}{x - 1}) + \sin^{- 1} (\frac{x - 1}{x + 1}), x > 0 . Find \frac{d y}{d x}

- 1 \leq x, y \leq 1

{sin}^{- 1} x + {sin}^{- 1} y = \frac{π}{2},

{cos}^{- 1} x + {cos}^{- 1} y .

s i n^{- 1} x + c o s^{- 1} x (| x | \geq 1)

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