Question

Find the value of $\theta$ for the equation $2\sin 2\theta =\sqrt{3}$

Answer 1

$2\sin 2\theta =\sqrt{3}$

$\Rightarrow \sin 2\theta =\frac{\sqrt{3}}{2}$

$2\theta =n\pi +(-1{)}^n(\pi /3)$

$\theta =\frac{n\pi }{2}+(-1{)}^n(\pi /6)$.