wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider a circuit with a potential difference of 5 V, with a current of 2 A flowing and the internal resistance of the battery at 0.8 ohms. Calculate the EMF in the circuit.


Open in App
Solution

Step 1: Given data

The potential difference V=5V , current I=2A , resistance r=0.8Ω

Step 2: Formula used

EMF in a circuit, ε=V+Ir[whereV=potentialdifference,I=current,andr=resistance]

Step 3: Calculating EMF in the circuit

Using the above formula and given data

ε=5V+2A×0.8Ωε=5V+1.6Vε=6.6V

Hence, the EMF of the circuit is 6.6V


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cell and Cell Combinations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon