Question

Find the value of $x$ and $y$ :-

$x-3y=3x-1=2x-y$

Answer 1

we have,

$x-3y=3x-1=2x-y$

Then,

$x-3y=3x-1and3x-1=2x-y$

$x-3y-3x+1=0$

$-2x-3y+1=0$

$2x+3y-1=0$…… (1)

Now,

$3x-1=2x-y$

$3x-1-2x+y=0$

$x+y-1=0$ …… (2)

By equation (1) and (2) to and we get,

$2x+3y-1=0$

$(x+y-1=0)\times 2$

Subtracting we get,

$y+1=0$

$y=-1$

Put the value of $y$ in equation (2) and we get,

$x=2$

Hence, $(x,y)=(2,-1)$ is the answer.