Find the value of x in
x+29=x+411
The correct option is D: 7
We have, x+29 = x+411
⇒11(x+2)=9(x+4)
⇒11x+22=9x+36
⇒2x=14
Find the H.C.F of the following expressions:
(1) x3 − 7x2 + 14x − 8 and x3 − 6x2 + 11x − 6
(2) 4a2 − 11a2 + 25a + 7 and 2a3 − 5a2 + 11a + 7
(3) x3 − 86x + 35 − 6x2 and x3 + 40 − 5x2 − 99x
(4) a3 − a2 − 7a + 3; a3 − 5a2 + 9a − 9 and a3 − 4a2 + 4a − 3.