Find the value of x for which 5 3 -4 - 5 3 -5 - 5 3 3x

[ 53 ]^( 4+( 5))= [ 53 ]^3x 3x= 9 #160; x= 3 ...

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Laws of Exponents for Real Numbers

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Find the value of $x$ for which ${(\frac{5}{3})}^{- 4} \times {(\frac{5}{3})}^{- 5} = {(\frac{5}{3})}^{3 x}$

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Find the value of x for which ${(\frac{5}{3})}^{- 4} \times {(\frac{5}{3})}^{- 5} = {(\frac{5}{3})}^{3 x}$

x

{(\frac{5}{3})}^{- 4} \times {(\frac{5}{3})}^{- 5} = {(\frac{5}{3})}^{3 x}

$If 3 (3 x + 5) + 12 = 2 (x + 3), then find the value of x .$

3^{x} = 81

2^{x - 3} = 1

3^{3 x - 5} = \frac{1}{9^{x}}

x = 2 + 5!,

x^{3} - 5 x^{2} + 33 x - 19

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