Find the value of x if $2^{x - 3} = 1$ .

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Solution

The correct option is D 3
Given, $2^{x - 3} = 1$

We know, for any non-zero integer $a$ , $a^{0} = 1$
$∴ 2^{x - 3} = 2^{0}$

Since the powers of 2 in the LHS and RHS are equal and the bases are the same, the exponents must be equal.
$∴ x - 3 = 0 \Rightarrow x = 3$

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