Question

Find the value of $x$, if AG $\parallel$ CE and AC $\parallel$ EF.

• A. $x={140}^o$
• B. $x={40}^o$
• C. $x={180}^o$
• D. Can't be found

Answer 1

The correct option is A $x={140}^o$

Given, AG $\parallel$ CE and $\angle ACE={40}^o$
$\angle CAG=\angle ACE$ [Alternate interior angles]
$\therefore \angle ACE={40}^o$
Given, AC $\parallel$ EF
So, $\angle CEF+\angle ACE={180}^o$ [Co-interior angles]
$\Rightarrow x+{40}^o={180}^o\Rightarrow x={140}^o$