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Question

Find the value of x if ∣ ∣x22x33x4x42x93x16x82x273x64∣ ∣=0?

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Solution

Given ∣ ∣x22x33x4x42x93x16x82x273x64∣ ∣=0Let=∣ ∣x22x33x4x42x93x16x82x273x64∣ ∣ApplyingC2=C22C1andC3=C33C1=∣ ∣x212x414x81140∣ ∣ApplyingR2=R2R1andR3=R3R1=∣ ∣x21222661242∣ ∣=(2)(6)∣ ∣x212113127∣ ∣=12[(x2)(76)1(74)+1(32)]=12[x23+1]=12(x4)
Given that =0=>12(x4)=0=>12x48=0=>x=4

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