Question

Find the value of $x$, if: $\frac{x-2}{3}=\frac{2x-1}{3}-1$.

Answer 1

Given, $\frac{x-2}{3}=\frac{2x-1}{3}-1$

$⟹$ $\frac{x-2}{3}=\frac{2x-1-3}{3}$ …[Cross-multiplying the denominators on the RHS]

$⟹$ $\frac{x-2}{3}=\frac{2x-4}{3}$ ...[On simplifying]

$⟹$ $x-2=2x-4$ ...[Multiplying $3$ on both sides]

$⟹$ $4-2=2x-x$ ...[Transposing $x$ terms to one side]

$⟹$ $x=2$.