Find the value of $x$ if ${log}_{5} 0.008 = x$

Open in App

Solution

$l o g_{5} 0.008 = x$

$\Rightarrow 5^{x} = 0.008$

$= \frac{8}{1000}$

$= \frac{1}{125}$

$= \frac{1}{5^{3}}$

$5^{x} = 5^{- 3}$

By equating powers

$∴ x = - 3$

Suggest Corrections

Similar questions

l o g_{1 / 2} 8

l o g_{5} 0.008

l o g_{5} 8

l o g_{7} \sqrt[3]{7}

{log}_{1 / 2} 8

{log}_{5} 0.008

{log}_{5} 3125

{log}_{7} \sqrt[3]{7}

x = {(\frac{3}{2})}^{2} \times {(\frac{2}{3})}^{- 4}

x = {(\frac{4}{5})}^{- 2} \div {(\frac{1}{4})}^{2}

\sqrt{x + \sqrt{x + \sqrt{x + . . . \infty}}} = 6

\sqrt{x} + 6 = x

x

Join BYJU'S Learning Program