Find the value of x if the distance between the points (2,−11) and (x,−3) is 10 units.
⇒√(x−2)2+82=10
⇒(x−2)2+64=100
⇒(x−2)2=36
⇒x−2=+6 or −6
⇒x=8 or −4
If the distance between points P (x, 2) and Q (3, –6) is 10 units, then x is