Question

Find the value of x if $x^3={\left(\frac{6}{5}\right)}^{-3}\times {\left(\frac{6}{5}\right)}^6.$

Answer 1

$x^3=({\frac{6}{5})}^{-3}{\times \left(\frac{6}{5}\right)}^6={\frac{6}{5}}^{-3+6}{x}^3=({\frac{6}{5})}^{3}So,x=\frac{6}{5}$