Question

Find the value of $x$ if
$x=4\sqrt{\frac{{\left(72.14\right)}^5\times \sqrt{45}}{(2.8{)}^3\times \sqrt{32}}}$

Answer 1

$\sqrt[4]{4\frac{(72.14{)}^5\times \sqrt{4}5}{(2.8{)}^3\times \sqrt{3}2}}$

$=\sqrt[4]{49^3\times {72}^2\times 7^3\times \frac{\sqrt{4}5}{\sqrt{3}2}}=\frac{4}{4}\sqrt{9^3\times {72}^2\times 7^3\times 3\frac{\sqrt{5}}{\sqrt{2}}}=9\times 3\times 72\times 7\times \sqrt{21\sqrt{\frac{5}{2}}}$

$=13608\sqrt{21\sqrt{\frac{5}{2}}}$