Find the value of X in the figure below- 80-70-60-100-

The correct option is A 80 We know that, ∠ABC + ∠CAB + ∠ACB = 180^∘ (angle sum property) ⇒ 90^∘ + 50^∘ + ∠ACB = 180^∘ ⇒ ∠ACB = 40^∘ ⇒ ∠KCL = ∠ACB = 40^∘ ...

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Standard VII

Mathematics

Sum of Interior Angles in a Triangle

Find the valu...

Question

Find the value of X in the figure below:

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100

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Solution

The correct option is A
80

We know that,

$∠$ ABC + $∠$ CAB + $∠$ ACB = 180 $^{\circ}$ (angle sum property)

⇒ 90 $^{\circ}$ + 50 $^{\circ}$ + $∠$ ACB = 180 $^{\circ}$

⇒ $∠$ ACB = 40 $^{\circ}$

⇒ $∠$ KCL = $∠$ ACB = 40 $^{\circ}$ (vertically opposite angles)

⇒ $∠$ KCL + $∠$ CLK + $∠$ X = 180 $^{\circ}$

⇒ 40 $^{\circ}$ + 60 $^{\circ}$ + $∠$ X = 180 $^{\circ}$

⇒ $∠$ X = 80 $^{\circ}$

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Find the value of X in the figure below:

The correct option is A 80 We know that, ∠ABC + ∠CAB + ∠ACB = 180∘ (angle sum property) ⇒ 90∘ + 50∘ + ∠ACB = 180∘ ⇒ ∠ACB = 40∘ ⇒ ∠KCL = ∠ACB = 40∘ (vertically opposite angles) ⇒ ∠KCL + ∠CLK + ∠X = 180∘ ⇒ 40∘ + 60∘ + ∠X = 180∘ ⇒ ∠X = 80∘