Find the value of x satisfying the equation logax+log√ax+log3√ax+..........loga√ax = a+12.
logax+2logax+.............+alogax = a+12
⇒ logax(1 + 2 + ........ + a) = a+12
⇒ logax. a(a+1)2 = a+12
⇒ x = a1a