Question

Find the value of $y$ if the distance between the points $(6,0)$ and $(3,y)$ is $5$ units.

Answer 1

Consider the given points.

$A(6,0),B(3,y)$

We know that the distance between two points

$d=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

$5=\sqrt{{(3-6)}^2+{(y-0)}^2}$

$5=\sqrt{9+y^2}$

$25=9+y^2$

$y^2=16$

$y=4$

Hence, this is the answer.