Find the value of z, if 3(5z−7)−2(9z−11)=4(8z−13)−17.
A
z=2
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B
z=4
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C
z=6
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D
z=7
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Solution
The correct option is Az=2 3(5z−7)−2(9z−11)=4(8z−13)−17 ⇒15z−21−18z+22=32z−52−17 ⇒−3z+1=32z−69 ⇒−3z−32z=−69−1 ⇒−35z=−70 ⇒z=2
Let's verify by substituting z = 2 in the given equation. 3(5z−7)−2(9z−11)=4(8z−13)−17 ⇒3[(5×2)−7]−2[(9×2)−11]=4[(8×2)−13]−17 ⇒3[10−7]−2[18−11]=4[16−13]−17 ⇒(3×3)+(−2×7)=(4×3)−17 ⇒9−14=12−17 ⇒−5=−5 ⇒LHS=RHS Therefore, it is correct.