1
Question
Solve the linear equation:3(5z−7)−2(9z−11)=4(8z−13)−17
Solve the linear equation:3(5z−7)−2(9z−11)=4(8z−13)−17
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Solution
The correct option is C. z=2
We have,3(5z−7)−2(9z−11)=4(8z−13)−17
⇒15z−21−18z+22=32z−52−17
⇒−3z+1=32z−69
⇒−3z−32z=−69−1 [Transposing 32z to LHS and 1 to RHS]
⇒−35z=−70
⇒z=−70−35=2
Hence, value of z=2.
The correct option is C. z=2
We have,3(5z−7)−2(9z−11)=4(8z−13)−17
⇒15z−21−18z+22=32z−52−17
⇒−3z+1=32z−69
⇒−3z−32z=−69−1 [Transposing 32z to LHS and 1 to RHS]
⇒−35z=−70
⇒z=−70−35=2
Hence, value of z=2.
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