Question

Find the values of $A,B$ and $C$ in the following .

$AB$
$\times$ $3$

______________

$CAB$

• A. $A=1,B=0,C=5$
• B. $A=5,B=1,C=0$
• C. $A=0,B=5,C=1$
• D. $A=5,B=0,C=1$

Answer 1

Answer: (D)

$A=5,B=0,C=1$

$AB$
$\times 3$
___________
$CAB$

$B\times 3=B$ holds only if $B=0$ or $5$

For $B=0,$

Use hit and trial to find the value of A. Value of A should be such that it holds , $A0$ $\times 3=$ $CA0$
$10\times 3=30$ (reject)
$20\times 3=60$ (reject)
$30\times 3=90$ (reject)
$40\times 3=120$ (reject)
$50\times 3=150$ (accept)
Clearly, $A=5$ satisfies given conditions.

Comparing $\left[150\right]$ with $\left[CAB\right]$
Therefore, $C=1,A=5,B=0$