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Super position theorem

Find the valu...

Question

Find the values of currents $I_{1}$ & $I_{2}$

7 s i n 3 t

, zero

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5 s i n 2 t, 5 + 5 s i n 2 t

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5, 5 s i n 2 t

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5 + 5 s i n 2 t

, zero

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Solution

The correct option is B $5 s i n 2 t, 5 + 5 s i n 2 t$
Apply super position theorem

Step 1: Deactivate $10 V$ source by short circuit

$I_{1} = \frac{10}{2 + j 2 - \frac{j}{2 (1 / 4)}} = \frac{10}{2} = 5 s i n 2 t A$

$I_{2} = \frac{10 s i n 2 t}{2} = 5 s i n 2 t A$

Step 2: Deactivate $10 s i n 2 t$ source by short circuit

Inductor become short circuit and capacitor become open circuit when connected with $D C$
$I_{1} = 0 A$
$I_{2} = \frac{10}{2} = 5 A$
$∴$ Net $I_{1} = 0 + 5 s i n 2 t = 5 s i n 2 t A$
$I_{2} = 5 + 5 s i n 2 t A$

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Similar questions

Find the value of $∣ ∣ ∣ \begin{matrix} 2 + i & 2 - i 1 + i & 1 - i \end{matrix} ∣ ∣ ∣$ if $i^{2} = - 1$ .

r_{1}

r_{2}

I_{1}

I_{2}

\frac{I_{1}}{I_{2}}

I_{1}

I_{2}

I_{1}, I_{2}

I_{3}

i = i_{1}

ω t + i_{2}

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