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Question

# Find the values of x and y if : 52+x+1yâˆ’4=2 62+xâˆ’3yâˆ’4=1 Here, x â‰  -2 and y â‰  4.

A

x = -2, y = 2

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B

x = 1, y = 7

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C

x = 0, y = 8

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D

x = 7, y = -8

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Solution

## The correct option is B x = 1, y = 7 Let p=12+x and q=1y−4 Thus, 5p + q = 2 .... (i) 6p - 3q = 1 .... (ii) On multiplying equation (i) by 3, we get 15p + 3q = 6 .... (iii) On adding equations (iii) and (ii), we get 21p = 7 ⇒p=13 On substituting the value of p in equation (i), we get 5×13+q=2 ⇒q=2−53 ⇒q=13 Now, p=12+x ⇒13=12+x ⇒x=1 Similarly q=1y−4 ⇒13=1y−4 ⇒y=7 ∴ x = 1 and y = 7

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