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Question

Find the values of x and y if :

52+x+1y4=2

62+x3y4=1

Here, x -2 and y 4.


A

x = -2, y = 2

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B

x = 1, y = 7

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C

x = 0, y = 8

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D

x = 7, y = -8

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Solution

The correct option is B

x = 1, y = 7


Let p=12+x and q=1y4

Thus, 5p + q = 2 .... (i)

6p - 3q = 1 .... (ii)

On multiplying equation (i) by 3, we get

15p + 3q = 6 .... (iii)

On adding equations (iii) and (ii), we get

21p = 7

p=13

On substituting the value of p in equation (i), we get

5×13+q=2

q=253

q=13

Now, p=12+x

13=12+x

x=1

Similarly q=1y4

13=1y4

y=7

x = 1 and y = 7


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