Find the vapour pressure of acetone in in a solution made by dissolving 1g of non volatile compound sulfanilamide in 10 g of acetone. The VP of pure acetone at that condition is 4?10^3mm of Hg(at mass of H = 1.008 g)

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Solution

The solution is as follows:

p_acetone = X_acetone . p⁰_acetone
= $\frac{n_{a c e t o n e}}{n_{a c e t o n e} + n_{s u l p h a n i l a m i d e}} p^{0} = \frac{\frac{10}{58.08}}{\frac{10}{58.08} + \frac{1}{172.2}} \times 4 \times 10^{3} = \frac{0.172}{0.172 + 0.005} \times 4 \times 10^{3} = 3.884 \times 10^{3}$

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Find the vapour pressure of acetone in in a solution made by dissolving 1g of non volatile compound sulfanilamide in 10 g of acetone. The VP of pure acetone at that condition is 4?10^3mm of Hg(at mass of H = 1.008 g)

The solution is as follows: pacetone = Xacetone . p0acetone = nacetonenacetone+nsulphanilamidep0=1058.081058.08+1172.2×4×103=0.1720.172+0.005×4×103=3.884×103