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Question

Find the vector and cartesian equations of the plane passing through the points A(1,1,2),B(1,2,1) and C(2,1,1)

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Solution

Given that plane passes through the points A(1,1,2),B(1,2,1),C(2,1,1)
The vectors BA=j+3k and CA=i2j+3k lies on the given plane
So the vector BA×CA will be perpendicular to given plane
n=BA×CA=9i+3jk
Equation of plane is
r.n=a.n
The plane through point a=A(1,1,2)(say),r=xi+yj+zk
a.n=14
Therefore the equation of the plane in Cartesian form is 9x+3yz=14


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