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Question

Find the vector equation of the following planes in non-parametric form.
(i) r=λ-2μ i^+3-μ j^+2λ+μ k^

(ii) r=2i^+2j^-k^+λi^+2j^+3k^+μ5i^-2j^+7k^

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Solution

i The given equation of the plane isr=λ-2μ i^+3-μ j^+2λ+μ k^r=0 i^+3 j^+0 k^+λ i^+0 j^+2 k^+μ -2 i^-j^+k^We know that the equation r=a+λb+μc represents a plane passing through a point whose position vector is a and parallel to the vectors b and c.Here, a=0 i^+3 j^+0 k^; b=i^+0 j^+2 k^; c=-2 i^-j^+k^Normal vector, n=b×c=i^j^k^102-2-11=2 i^-5 j^-k^The vector equation of the plane in scalar product form isr. n=a. nr. 2 i^-5 j^-k^ = 0 i^+3 j^+0 k^. 2 i^-5 j^-k^r. 2 i^-5 j^-k^ = 0 - 15 + 0r. 2 i^-5 j^-k^ + 15 = 0

ii We know that the equation r=a+λb+μc represents a plane passing through a point whose position vector is a and parallel to the vectors b and c.Here, a=2 i^+2 j^- k^; b=i^+2 j^+3 k^; c=5 i-2 j^+7 k^Normal vector, n=b×c=i^j^k^1235-27=20 i^+8 j^-12 k^The vector equation of the plane in scalar product form isr. n=a. nr. 20 i^+8 j^-12 k^=2 i^+2 j^- k^. 20 i^+8 j^-12 k^r. 4 5 i^+2 j^-3 k^=40+16+12r. 4 5 i^+2 j^-3 k^=68r. 5 i^+2 j^-3 k^=17

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