Question

Find the velocity of a projectile at the highest point, if it is projected with a speed $15$ m $s^{-1}$, in the direction ${45}^o$ above horizontal. [take $g=10m{s}^{-2}$]

Answer 1

At highest point the final velocity will be $15\times cos45=10.6\frac{m}{sec}$ in the horizontal direction (parallel to ground).

At highest point the y component of velocity becomes zero so only velocity in the horizontal direction remains.