Find the voltage drop across a capacitor connected with a resistance and battery of $60 V$ in series after a long time.

0 V

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60 V

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30 V

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38 V

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Solution

The correct option is C $60 V$
In a RC-series circuit excited by a DC source, at steady state, no current flows. So, all the voltage drop is across the capacitor. Therefore, the voltage drop will be $60 V$ .
The formula is $V = V_{0} (1 - e^{\frac{- t}{R C}})$ .

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