Question

Find the volume of the frustum cone whose base and top radius is 11 in and 6 in respectively. The height of the cone is 36 in. (Use $\pi$ = 3.14).

• A. 8,302.64 in${}^3$
• B. 8,202.64 in${}^3$
• C. 8,402.64 in${}^3$
• D. 8,102.64 in${}^3$

Answer 1

The correct option is C 8,402.64 in${}^3$

Volume of the frustum cone is $V=\frac{\pi h}{3}(R^2+Rr+r^2)$
$R=11in,r=6in,h=36in$
$V=(3.14\times 36)/\left(3\right)[{11}^2+11\times 6+6^2]$
$=3.14\times 12[121+66+36]$
$=37.68\left[223\right]$
$=8,402.64i{n}^3$