Question

The base and top radius of a cone is 36 cm and 16 cm respectively. The height of the cone is 12.6 cm. What is the volume of frustum of a cone? (Use $\pi$ = 3.14).

• A. 28,064.064 cm${}^3$
• B. 27,064.064 cm${}^3$
• C. 26,064.064 cm${}^3$
• D. 25,064.064 cm${}^3$

Answer 1

Answer: (A)

28,064.064 cm${}^3$

Volume of the frustum cone V = $\frac{\pi h}{3}(R^2+Rr+r^2)$

$R=36cm,r=16cm,h=12.6cm$

$V=(3.14\times 12.6)/\left(3\right)[362+36\times 16+162]$

$=3.14\times 4.2[1,296+576+256]$

$=13.188[2,128]$

$=28,064.064c{m}^3$