Question

The base and top diameter of a cone is 12 cm and 2 cm respectively. The height of the cone is 360 cm. What is the volume of frustum of a cone? (Use $\pi$ = 3.14).

• A. 259,238.4 cm
• B. 259,238.4 m${}^3$
• C. 259,238.4 cm${}^3$
• D. 259,238.4 mm${}^3$

Answer 1

Answer: (C)

259,238.4 cm${}^3$

Volume of the frustum cone is $V=\frac{\pi h}{3}(R^2+Rr+r^2)$

D = 12 cm, d = 2 cm, h = 360 cm

Diameter = radius/2

Radius = 2 $\times$ diameter

Therefore, R = 24 cm, r = 4 cm

$V=(3.14\times 360)/\left(3\right)[{24}^2+24\times 4+4^2]$

$=3.14\times 120[576+96+16]$

$=$ 376.8[688]

$=$ 259,238.4 cm${}^3$