Question

Find the volume of the frustum cone whose base and top radius is $8$ cm and $4$ cm respectively. The height of the cone is $5$ cm. (Use $\pi =\frac{22}{7}$).

(Insert answer in nearest integer).

Answer 1

Volume of the frustum cone = $\frac{1}{3}\pi h(R^2+r^2+Rr)$

$=\frac{1}{3}\pi \times 5(8^2+4^2+32)$
$=\frac{1}{3}\pi \times 560$
$=\frac{1}{3}\times \frac{22}{7}\times 280$
$=586.66c{m}^3$