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Nuclear Force

Find the wave...

Question

Find the wavelength of electron in the 2nd orbit of $H e^{+}$ ion

3.3 \circ A

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6.42 \circ A

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1.47 \circ A

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2.37 \circ A

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Solution

The correct option is A $3.3 \circ A$
$2 π r = n λ$
$2 \times π \times 0.529 \times \frac{n^{2}}{Z} = n λ$
$λ = \frac{2 \times π \times 0.529 \times n^{2}}{n \times Z} λ = \frac{2 \times 3.14 \times 0.529 \times 2^{2}}{2 \times 2}$
$λ = 3.3 \circ A$

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