The correct option is
B 200 mLet
, vr= velocity of river
vbr= velocity of river in still water
w= width the river
Given, tmin=10minorwvbr---------------(1)
Drift in this case will be,
x=vrt
∴120=10vr-------------------------(2)
Shortest path is taken when vb is along AB. In this case,
vb=√v2br−v2r
Now, 12.5=wvb=w√v2br−v2r----------------(3)
solving these three equations, we get
vbr=20m/min, vr=12m/min and w=200m.
Hence,
option (B) is correct answer.