Question

Find three consecutive odd numbers whose sum is $147$.

Answer 1

Step 1: Calculate one of the numbers

Let us assume the three consecutive even numbers as $x,x+2$ and $x+4$.

It is given that the sum of these three numbers is $147$.

$\therefore x+x+2+x+4=147$

$\Rightarrow$ $3x+6=147$

$\Rightarrow$ $3x=147-6$

$\Rightarrow$ $x=\frac{141}{3}$

$\Rightarrow$ $x=47$

Step 2: Calculate the other two numbers

Therefore,

$x+2=47+2=49$

$x+4=47+4=51$

Hence, the three consecutive odd numbers are $47,49$ and $51$.