Question

Find time, if principal $=$$1200$, rate $=$$12\%$$p.a$amount $=Rs1776$.

Answer 1

Given,

Principal,$P$ $=$$1200$,

Rate of interest,$R$ $\%$$=$$12\%$$p.a$

Amount,$A$$=Rs1776$

Time, $T$ $=............$

We know that,

$T$ $=\frac{100\times I}{P\times R}$ , when $I$ , $P$, $R$ are given.

We need to find Interest $I$ ,

i.e $I$ $=$$A$$-$$P$

$I$ $=$$Rs1776$ $-$ $Rs1200$

$I$ $=$$Rs576$

Put the values of $P$, $R$ , $I$ in the below formula , To find Time, $T$ :

$T$$=\frac{100\times I}{P\times R}$

$T$$=\frac{100\times 576}{1200\times 12}$

$T$$=\frac{57600}{14400}$ ( divide numerator and denominator by $100$ )

$T$$=\frac{576}{144}$ ( divide $576$ by $144$, we get $4$)

$T$$=4$.

Therefore, the time $T$ is $4years$.

Hence, the answer for the given question is $4years$.