Question

Find total number of stereoisomers for each compound given below:
$C{H}_3-CH=CH-\underset{Br}{\underset{|}{C}}H-C{H}_3$

• A. $6$
• B. $5$
• C. $4$
• D. none

Answer 1

The correct option is C $4$

For unsymmetrical molecule total number of stereoisomers= $2^n$

$n$= number of stereoisomers

(Refer to Image)

There are $2$ asymmetric centre. Thus, number of stereoisomers= $2^n$

$\Rightarrow 2^2=4$