Question

Find two consecutive odd numbers whose sum is $128.$

Answer 1

Find the required odd numbers

Let two consecutive number be $x\&x+2$

From the given condition, $x+(x+2)=128$

$\Rightarrow 2x+2=128$

Subtracting $2$ from both the sides, we get

$$\begin{gathered} \Rightarrow 2x+2-2=128-2 \\ \Rightarrow 2x=126 \end{gathered}$$

Dividing both sides of equation by $2$, we get

$$\begin{gathered} \Rightarrow \frac{2x}{2}=\frac{126}{2} \\ \Rightarrow x=63 \end{gathered}$$

And the other odd number is

$\begin{array}{rcl}x+2& =& 63+2\\ & =& 65\end{array}$

Hence the required odd numbers are $63$ and $65$.