Find three consecutive positive even integers whose sum is 90.
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Solution
Let the three consecutive positive even integers be x, (x+2) and (x+4). Let x be the even number. Then, x+x+2+x+4=90 ⇒3x=90−6⇒3x=84 ⇒x=843=28 ∴The required numbers are 28, 30 and 32.