Question

Find two numbers such that one of them exceeds the other by $9$ and their sum is $81$

Answer 1

Let the smaller number be $x$

The larger number will be $x+9$.

Given that their sum is $81$.

Therefore, $x+x+9=81$

$\Rightarrow 2x+9=81$

$\Rightarrow 2x=81-9$

$\Rightarrow 2x=72$

$\Rightarrow x=36$

Smaller number is $36$.

Now, the larger number will be $x+9=36+9=45$.