Find two solutions of $3 x + 4 y = 12$

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Solution

Finding two solution for equation $3 x + 4 y = 12$ :
Putting the value of $x = 0$ in equation $3 x + 4 y = 12$
$\Rightarrow 3 (0) + 4 y = 12$
$\Rightarrow 4 y = 12$
$\Rightarrow y = 3$
Thus, $(0, 3)$ is a solution of equation $3 x + 4 y = 12$
Putting the value of $y = 0$ in equation $3 x + 4 y = 12$
$\Rightarrow 3 x + 4 (0) = 12$
$\Rightarrow 3 x = 12$
$\Rightarrow x = 4$
Thus, $(4, 0)$ is a solution of equation $3 x + 4 y = 12$
Therefore, $(0, 3), (4, 0)$ are two solution of equation $3 x + 4 y = 12$

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