Question

Find value: $(-\frac{1}{27}){-}^{\frac{2}{3}}$ ?

Answer 1

${\left(x^a\right)}^b=x^{a\ast b}$

$\frac{1}{x^a}=x^{-a}$

${\left(\frac{1}{27}\right)}^{\frac{1}{3}\ast -2}={\left({\left(\frac{1}{27}\right)}^{\frac{1}{3}}\right)}^{-2}={\left(\frac{1^{\frac{1}{3}}}{{27}^{\frac{1}{3}}}\right)}^{-2}={\left(\frac{1}{3}\right)}^{-2}=\frac{1^{-2}}{3^{-2}}=\frac{1}{3^{-2}}=3^2=9$