Find value of x- -2-x1-12

nbsp; √(2)=(x)^1/12 Cubing both sides, we get nbsp; = gt;2=x^3/12 = gt;2=x^1/4 = gt;2^4=x = gt;x=16 ...

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Byju's Answer

Standard VIII

Mathematics

Inverse Proportion

Find value of...

Question

Find value of $x$ :
$\sqrt[3]{2} = {(x)}^{1 / 12}$

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Solution

$\sqrt[3]{2} = {(x)}^{1 / 12}$
Cubing both sides, we get
$=> 2 = x^{3 / 12}$
$=> 2 = x^{\frac{1}{4}}$
$=> 2^{4} = x$
$=> x = 16$

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Find value of x:3√2=(x)1/12

3√2=(x)1/12Cubing both sides, we get =>2=x3/12=>2=x14=>24=x=>x=16

Find value of $x$ :
$\sqrt[3]{2} = {(x)}^{1 / 12}$

$\sqrt[3]{2} = {(x)}^{1 / 12}$
Cubing both sides, we get
$=> 2 = x^{3 / 12}$
$=> 2 = x^{\frac{1}{4}}$
$=> 2^{4} = x$
$=> x = 16$